Find the perimeter of rectangle whose
a) $ l=50 \mathrm{~cm}, b=30 \mathrm{~cm} $
b) $ l=2 \cdot 5 \mathrm{~cm}, b=1 \cdot 5 \mathrm{~cm} $
Given:
The measurements of rectangle are:
a) \( l=50 \mathrm{~cm}, b=30 \mathrm{~cm} \)
b) \( l=2 \cdot 5 \mathrm{~cm}, b=1 \cdot 5 \mathrm{~cm} \)
To do:
We have to find the perimeter of the given rectangles.
Solution:
We know that,
Perimeter of a rectangle of length $l$ and breadth $b$ is $2(l+b)$.
Therefore,
(i) Perimeter of the rectangle of measurements ( $l=50\ cm, b=30\ cm) =2(50+30)\ cm$
$=2(80)\ cm$
$=160\ cm$.
(ii) Perimeter of the rectangle of measurements ( $l=2.5\ cm, b=1.5\ cm) =2(2.5+1.5)\ cm$
$=2(4)\ cm$
$=8\ cm$.
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