Find the perimeter of a rectangle whose adjacent sides are $x- 3y+5z$ and $3x- 5y-2z$.

Given:

The adjacent sides of a rectangle are $x- 3y+5z$ and $3x- 5y-2z$.

To do:

We have to find the perimeter of the rectangle.
Solution:
Let $l=x- 3y+5z$ and $b=3x- 5y-2z$

Perimeter of the rectangle $=2(l+b)$

Therefore,

Perimeter $=2(x- 3y+5z+3x- 5y-2z)$

$=2[(x+3x)+(-3y-5y)+(5z-2z)]$

$=2(4x-8y+3z)$

$=8x-16y+6z$

The perimeter of the rectangle is $8x-16y+6z$.

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Updated on: 10-Oct-2022

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