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Find the number of digit in the square root of the given number ( without any calculation): $529$.
Given: A number $529$.
To do: To find the number of digit in the square root of the given number $( without\ any\ calculation)$.
Solution:
Given number$=529$
Number of digits in the given number, $n=3$, which is odd.
If $n$ is odd, then number of digits in the square root of the given number$=\frac{n+1}{2}$
$=\frac{3+1}{2}$
$=\frac{4}{2}$
$=2$
Thus, there are $2$ digits in the square root of $529$.
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