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Find the number of digit in the square root of the given number ( without any calculation): $4601025$.
Given: A number $4601025$.
To do: To find the number of digit in the square root of the given number $( without\ any\ calculation)$.
Solution:
Given number$=4601025$
Number of digits in the given number, $n=7$
$\therefore$ Number of digits in the square root of the given number$=\frac{n+1}{2}$ [$\because n$ is odd]
$=\frac{7+1}{2}$
$=\frac{8}{2}$
$=4$
Thus, the number of digits in the square root of the number $4601025$ is $4$.
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