Find the mode of the following distribution.
Class-interval:0-1010-2020-3030-4040-5050-6060-7070-80
Frequency:5871228201010


To do:

We have to find the mode of the given distribution.

Solution:

The frequency of the given data is as given below:

Class-interval($x_i$):
Frequency$(f_i$):
0-10
5
10-20
8
20-30
7
30-40
12
40-50
28
50-60
20
60-70
10
70-80
10

We observe that the class interval of 40-50 has the maximum frequency(28).

Therefore,

It is the modal class.

Here,

$l=40, h=10, f=28, f_1=12, f_2=20$

We know that,

Mode $=l+\frac{f-f_1}{2 f-f_1-f_2} \times h$

$=40+\frac{28-12}{2 \times 28-12-20} \times 10$

$=40+\frac{16}{56-32} \times 10$

$=40+\frac{16}{24} \times 10$

$=40+\frac{20}{3}$

$=40+6.67$

$=46.67$

Hence, the mode of the given distribution is 46.67.  

Updated on: 10-Oct-2022

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