Find the missing frequency $p$ for the following distribution whose mean is 7.68.
$x$:35791113
$f$:6815$p$84.


Given:

The mean of the given data is 7.68.

To do:

We have to find the value of $p$.

Solution:

$x$$f$$f \times\ x$
3618
5840
715105
9$p$$9p$
11888
13452
Total$41+p$$303+9p$

We know that,  

Mean$=\frac{\sum fx}{\sum f}$

Therefore,

Mean $7.68=\frac{303+9p}{41+p}$

$7.68(41+p)=303+9p$

$314.88+7.68p=303+9p$

$9p-7.68p=314.88-303$

$p=\frac{11.88}{1.32}$

$p=\frac{1188}{132}$

$p=9$

The value of $p$ is $9$.

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Updated on: 10-Oct-2022

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