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Find the least square number which is exactly divisible by 8, 9 and 10
Given:
8, 9, 10
To find:
We have to find the least square number which is exactly divisible by 8, 9 and 10.
Solution:
First, we need to find the LCM of the given numbers i.e., 8, 9 and 10.
Now,
Writing all the numbers as a product of their prime factors:
Prime factorization of 8:
- $2\times2\times2 = 2^3$
Prime factorization of 9:
- $3\times 3 = 3^2$
Prime factorization of 10:
- $2\times5 = 2^1\times 5^1$
Highest power of each prime number:
- $2^3 , 3^2 , 5^1$
Multiplying these values together:
$2^3\times 3^2\times5^1 = 360$
Thus,
LCM $(8, 9, 10) = 360$
We know that in a perfect square all the prime factors of that number are in pairs. So, we need to multiply 360 with 2 and 5 to make it a perfect square.
$360\times 2\times 5 = 3600$
So, the least square number which is exactly divisible by 8, 9 and 10 is 3600.
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