Find The Least Number Which When Divided By 6,15 And 18 Leaves Remainder 5 In Each Case.

To do: find the least number which when divided by615 and 18 leaves Remainder 5 in each case

Solution:

To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number.

L.C.M. of 6, 5 and 18 

6 = 2$\times$3

15 = 3$\times$5

18 = 2$\times$3$\times$3

L.C.M. of 6, 15 and 18 = 2$\times$3$\times$3$\times$5

                                         = 90

Now, 

5 $+$ 90 = 95

Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.

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Updated on: 10-Oct-2022

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