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Find the least number of three digits which is perfect square.
To do:
We have to find the least number of three digits which is perfect square.
Solution:
The smallest three digit number is $100$.
We know that,
$9^2 = 81$, $10^2 = 100$ and $11^2 = 121$
Therefore,
$100$ is the least three digit number which is a perfect square.
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