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Find the LCM of 48, 64, 72, 96, 106.
Given: 48, 64, 72, 96, 106.
To find: Here we have to find LCM of 48, 64, 72, 96, 106.
Solution:
Writing down the numbers as a product of their prime factors:
Prime factorization of 48:
- 2 $\times$ 2 $\times$ 2 $\times$ 2 $\times$ 3 = 24 $\times$ 31
Prime factorization of 64:
- 2 $\times$ 2 $\times$ 2 $\times$ 2 $\times$ 2 $\times$ 2 = 26
Prime factorization of 72:
- 2 $\times$ 2 $\times$ 2 $\times$ 3 $\times$ 3 = 23 $\times$ 32
Prime factorization of 96:
- 2 $\times$ 2 $\times$ 2 $\times$ 2 $\times$ 2 $\times$ 3 = 25 $\times$ 31
Prime factorization of 106:
- 2 $\times$ 53 = 21 $\times$ 531
Finding the highest power of each prime number:
- 26 , 32 , 531
Multiplying these values together:
- 26 $\times$ 32 $\times$ 531 = 30528
Thus,
LCM(48, 64, 72, 96, 106) = 30528
So, LCM of 48, 64, 72, 96, 106 is 30528.
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