Find the lateral surface area and total surface area of a cuboid of length $80\ cm$, breadth $40\ cm$ and height $20\ cm$.

Given:

A cuboid of length $80\ cm$, breadth $40\ cm$ and height $20\ cm$.

To do:

We have to find the lateral surface area and total surface area of the cuboid.

Solution:

Length of the cuboid $(l) = 80\ cm$

Breadth of the cuboid $(b) = 40\ cm$

Height of the cuboid $(h) = 20\ cm$

Lateral surface area of the cuboid $= 2h(l + b)$

$= 2 \times 20(80 + 40)$

$= 40 \times 120$

$= 4800\ cm^2$

Total surface area of the cuboid $= 2(lb + bh + lh)$

$= 2(80 \times 40 + 40 \times 20 + 20 \times 80)$

$= 2(3200 + 800 + 1600)$

$= 5600 \times 2$

$= 11200\ cm^2$