Find the largest angle of a triangle which are in the ratio $4:3:2$.

Given:

The angles of a triangle are in the ratio $4:3:2$.

To do:

We have to find the largest angle of the triangle.

Solution:

Let the angles of the triangle be $4x, 3x$ and $2x$.

We know that,
Sum of the angles in a triangle is $180^o$.
Therefore,

$4x+3x+2x=180^o$

$9x=180^o$

$x=\frac{180^o}{9}$

$x=20^o$

$4x=4(20^o)=80^o$

$3x=3(20^o)=60^o$

$2x=2(20^o)=40^o$
The largest angle of the given triangle is $80^o$.

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Updated on: 10-Oct-2022

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