Find the height of a trapezium, the sum of lengths of whose bases is $39cm$, and whose area is $65cm^2.$

Given: The sum of lengths of trapezium's bases is $39cm$, and whose area is $65cm^2.$

To do: Find the height of the trapezium

Solution:

Given the area of trapezium = 65 sq cm

Sum of bases = $ (base1 + base2) = 39$ cm

The formula for Area of trapezium

=$\frac{1}{ 2} \times height(base1 + base2)$ 

= $\frac{1}{2} \times h \times 39 = 65$

h = $65 x \frac{2}{39} = \frac{10}{3}$

height  = $\frac{10}{3} cm = 3 \frac{1}{3}$ cm

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

47 Views

Kickstart Your Career

Get certified by completing the course

Get Started