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Find the HCF of 84, 56, 35 and 112.
Given: The numbers are 84, 56, 35 and 112
To do: Find HCF of the given numbers
Solution:
$84 = 2 \times 2 \times 3 \times 7$
$56 = 2 \times 2 \times 2 \times 7$
$35 = 3 \times 7$
$112 = 2 \times 2 \times 2 \times 2 \times 7$
Therefore, HCF of 84, 56, 35 and 112 = 7
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