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Find the HCF of 48, 49 and 54.
Given:
Given numbers are 48, 49 and 54.
To find:
We have to find the HCF of 48, 49 and 54.
Solution:
Factorisation of 48:
$48=2\times 2 \times 2 \times 2\times 3$
Factorisation of 49:
$49=7\times 7$
Factorisation of 54:
$54=2 \times 3 \times 3\times 3$
There are no common factors in 48, 49 and 54.
Therefore, the HCF of 48, 49 and 54 is 1.
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