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Find the greatest number of two digits which is a perfect square.
To do:
We have to find the greatest number of two digits which is a perfect square.
Solution:
The greatest two digit number is $99$.
We know that,
$9^2 = 81$ and $10^2 = 100$
$99$ is in between $81$ and $100$
Therefore,
$81$ is the greatest two-digit number which is a perfect square.
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