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# Find the greatest number of three digits which is a perfect square.

To do:

We have to find the greatest three digit number which is a perfect square.

Solution:

The greatest $3$ digit number$=999$

Square root of 999 is,

31 | |

3 | 999 9 |

61 | 99 61 |

38 |

The remainder is 38.

Therefore, if we subtract 38 from 999 then the new number will be a perfect square.

The required number is $999-38$

$=961$

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