Find the greatest number of three digits which is a perfect square.

To do:

We have to find the greatest three digit number which is a perfect square.

Solution:

The greatest $3$ digit number$=999$

Square root of 999 is,

	31
3	999 9
61	99   61
	38

The remainder is 38.

Therefore, if we subtract 38 from 999 then the new number will be a perfect square.

The required number is  $999-38$

$=961$