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Find the greatest number of 4-digits which is a perfect square.
To do:
We have to find the greatest four digit number which is a perfect square.
Solution:
The largest $4$ digit number$=9999$
$100^2=10000$ or $1$ greater than the largest $4$ digit number.
This means that the closest square root of the largest perfect square is most likely $99$.
Therefore, $99^2=( 9801)$ is the largest perfect square of four digits.
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