Find the following products:
$\frac{4}{3}a(a^2 + b^2 - 3c^2)$

Given:

$\frac{4}{3}a(a^2 + b^2 - 3c^2)$

To do:

We have to find the given product.

Solution:

$\frac{4}{3} a(a^{2}+b^{2}-3 c^{2})=\frac{4}{3} a \times a^{2}+\frac{4}{3} a \times b^{2}+\frac{4}{3} a \times(-3 c^{2})$

$=\frac{4}{3} a^{1+2}+\frac{4}{3} a \times b^{2}-4 \times a \times c^{2}$

$=\frac{4}{3} a^{3}+\frac{4}{3} a b^{2}-4 a c^{2}$

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Updated on: 10-Oct-2022

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