Find the following products:
$-11y^2 (3y + 7)$

Given:

$-11y^2 (3y + 7)$

To do:

We have to find the given product.

Solution:

$-11y^2 (3y + 7)=-11y^2 \times 3y - 11y^2 \times 7$

$= -33y^{2+1}-77y^2$

$= -33y^3-77y^2$

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Updated on: 10-Oct-2022

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