Find the following product.
$(-4x^2) \times (-6xy^2) \times (-3yz^2)$

Given:

$(-4x^2) \times (-6xy^2) \times (-3yz^2)$

To do:

We have to find the given product.

Solution:

$(-4x^2) \times (-6xy^2) \times (-3yz^2) = (-4) \times (-6) \times (-3) x^2 \times x \times y^2 \times y \times z^2$

$= -72x^{2+1} \times y^{2+1} \times z^2$

$= -72x^3y^3z^2$