Find the following product and reduce them to the lowest form (If possible):
$ 3 \frac{8}{19} \times 5 \frac{3}{7} \times3 \frac{10}{13}$

To do: Find the following product and reduce them to the lowest form 

Solution:

 $ 3 \frac{8}{19} \times 5 \frac{3}{7} \times3 \frac{10}{13}$

Convert the mixed fractions into improper fraction first

$3\frac{8}{19}=\frac{65}{19}$  

$5 \frac{3}{7}= \frac{38}{7} $

$3 \frac{10}{13}=\frac{49}{13}$

Now , 

$\frac{65}{19}\times  \frac{38}{7}\times \frac{49}{13} $

$\frac{5}{1}\times  \frac{2}{1}\times \frac{7}{1} $

[$7\times 7 =49 and 13\times 5 =65\ and \ 19\times2 $]

=$70$

Therefore the answer is $70$

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Updated on: 10-Oct-2022

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