# Find The first four terms of an AP, whose first term is $â€“2$ and the common difference is $â€“2$.

**Given: **First term, $a=-2$ and common difference, $d=-2$.

**To do: **To find first four terms of the A.P.

**Solution:**

As given, First term$( a)=-2$

Common difference$( d)=-2$

$\therefore\ 2^{nd}$ term$=a+d=-2-2=-4$

$\Rightarrow\ 3^{rd}$ term$a+2d=-2+2( -2)=-6$

$\Rightarrow\ 4^{th}$ term $a+3d=-2+3( -2)=-8$

Therefore, the A.P. is $-2,\ -4,\ -6,\ -8,$ ......

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