Find the distance of the point $( 6,\ -8)$ from the origin.

Given: Point $( 6,\ -8)$.

To do: To find the Distance of the point $( 6,\ -8)$ from the origin.

Solution: 

As given, $x_1=0,\ y_1=0,\ x_2=6,\ y_2=-8$

$\therefore$ Distance of the point $( 6,\ -8)$ from the origin $=\sqrt{( x_2-x_1)^2+( y_2-y_1)^2}$

$=\sqrt{ ( 6-0)^2+( -8-0)^2}$

$=\sqrt{36+64}$

$=\sqrt{100}$

$=10\ units$

Thus, distance of the point from the origin is $10\ units$

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Updated on: 10-Oct-2022

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