Find the distance of a point $R( -6,\ -8)$ from the origin.

Given: A point $R( -6,\ -8)$.

To do: To find its distance from the origin.

Solution:

Given point is $R( -6,\ -8)$.

We know  if there two points $( {x_{1},\ y_{1})\ and\ ( x_2},\ y_{2})$,

Distance between the two points $=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

Here, $x_{1}=-6,\ y_{1}=-8,\ x_{2}=0\ and\ y_{2}=0$, On substituting these value in formula,

Distance from the origin $=\sqrt{( 0-( -6))^{2}+(0-( -8))^{2}}$

$=\sqrt{( 6)^{2}+( 8)^{2}}$

$=\sqrt{36+64}$

$=\sqrt{100}$

$=\pm10$

Since, speed can't be negative, therefor we reject the value $x=-10$.

$\therefore$ Distance of the point $R( -6,\ -8)$ is $10$ unit.

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Updated on: 10-Oct-2022

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