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Find the discriminant of the quadratic equation $3\sqrt{3}x^2+10x+\sqrt{3}$.
Given: The quadratic equation $3\sqrt{3}x^2+10x+\sqrt{3}$.
To do: To find the discriminant of the quadratic equation.
Solution:
As given, quadratic equation $3\sqrt{3}x^2+10x+\sqrt{3}=0$.
Here, $a=3\sqrt{3},\ b=10\ and\ c=\sqrt{3}$
$\therefore$ Its discriminant, $D=b^2-4ac$
$= (10)^2-4\times3\sqrt{3}\times\sqrt{3}$
$=100-4\times12\times3$
$=100-36$
$=64$
Thus, discriminant of the given quadratic equation is $64$.
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