Find the discriminant of the quadratic equation $3\sqrt{3}x^2+10x+\sqrt{3}$.


Given: The quadratic equation $3\sqrt{3}x^2+10x+\sqrt{3}$.

To do: To find the discriminant of the quadratic equation.

Solution:

As given,  quadratic equation $3\sqrt{3}x^2+10x+\sqrt{3}=0$.

Here, $a=3\sqrt{3},\ b=10\ and\ c=\sqrt{3}$

$\therefore$ Its discriminant, $D=b^2-4ac$

$= (10)^2-4\times3\sqrt{3}\times\sqrt{3}$

$=100-4\times12\times3$

$=100-36$

$=64$

Thus, discriminant of the given quadratic equation is $64$. 



Tutorialspoint
Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

734 Views

Kickstart Your Career

Get certified by completing the course

Get Started
Advertisements