Find the derivative of $V=2x^3+3x+9$.

Given:

$V=2x^3+3x+9$.

To do:

We have to find the derivative of $V=2x^3+3x+9$.

Solution:

Let $f(x)=2x^3+3x+9$
$f'(x)=\frac{d(2x^3+3x+9)}{dx}$

$=2(3)x^{3-1}+3x^{1-1}+0$

$=6x^2+3x^0$

$=6x^2+3$

The derivative of $V=2x^3+3x+9$ is $6x^2+3$.

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Updated on: 10-Oct-2022

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