Find the cube of
(i) $-11$.
(ii) $-12$
(iii) $-21$.

To find: 

We have to find the cube of the given numbers.

Solution:

(i) $(-11)^3=-11\times-11\times-11$

$=-(11\times11\times11)$

$=-1331$

(ii) $(-12)^3=-12\times-12\times-12$

$=-(12\times12\times12)$

$=-1728$

(iii) $(-21)^3=-21\times-21\times-21$

$=-(21\times21\times21)$

$=-9261$

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Updated on: 10-Oct-2022

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