Find the common difference and write the next four terms of each of the following arithmetic progressions :$0, -3, -6, -9, ……$

Given:

Given A.P. is $0, -3, -6, -9, ……$.
To do:

We have to find the common difference and write the next four terms of the given A.P.
Solution:
 The common difference of an A.P. is the difference between any two consecutive terms.

Here,

$a_1=0, a_2=-3, a_3=-6, a_4=-9$

$d=a_2-a_1=-3-0=-3$

$a_5=a_4+d=-9+(-3)=-9-3=-12$

$a_6=a_5+d=-12+(-3)=-12-3=-15$

$a_7=a_6+d=-15+(-3)=-15-3=-18$

$a_8=a_7+d=-18+(-3)=-18-3=-21$

The common difference of the given A.P. is $-3$ and the next four terms are $-12, -15, -18$ and $-21$. 

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Updated on: 10-Oct-2022

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