Find the centroid of the triangle whose vertices are:$(-2, 3), (2, -1), (4, 0)$
Given:
The points $(-2, 3), (2, -1), (4, 0)$ are the vertices of a triangle.
To do:
We have to find the centroid of the given triangle.
Solution:
We know that,
Coordinates of the centroid of a triangle are $(\frac{Sum\ of\ abscissa}{3}, \frac{Sum\ of\ ordinates}{3})$
Therefore,
The coordinates of the centroid of the given triangle are,
$(\frac{(-2)+2+4}{3}, \frac{3+(-1)+0}{3})$
$=(\frac{4}{3}, \frac{3-1}{3})$
$=(\frac{4}{3}, \frac{2}{3})$
The centroid of the given triangle is $(\frac{4}{3}, \frac{2}{3})$.
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