Find the centroid of the triangle whose vertices are:$(-2, 3), (2, -1), (4, 0)$

Given:

The points $(-2, 3), (2, -1), (4, 0)$ are the vertices of a triangle.

To do:

We have to find the centroid of the given triangle.

Solution:

We know that,

Coordinates of the centroid of a triangle are $(\frac{Sum\ of\ abscissa}{3}, \frac{Sum\ of\ ordinates}{3})$

Therefore,

The coordinates of the centroid of the given triangle are,

$(\frac{(-2)+2+4}{3}, \frac{3+(-1)+0}{3})$

$=(\frac{4}{3}, \frac{3-1}{3})$

$=(\frac{4}{3}, \frac{2}{3})$

The centroid of the given triangle is $(\frac{4}{3}, \frac{2}{3})$.