Find the centroid of the triangle whose vertices are:$(1, 4), (-1, -1), (3, -2)$
Given:
The points $(1, 4), (-1, -1), (3, -2)$ are the vertices of a triangle.
To do:
We have to find the centroid of the given triangle.
Solution:
We know that,
Coordinates of the centroid of a triangle are $(\frac{Sum\ of\ abscissa}{3}, \frac{Sum\ of\ ordinates}{3})$
Therefore,
The coordinates of the centroid of the given triangle are,
$(\frac{1+(-1)+3}{3}, \frac{4+(-1)+(-2)}{3})$
$=(\frac{3}{3}, \frac{4-3}{3})$
$=(1, \frac{1}{3})$
The centroid of the given triangle is $(1, \frac{1}{3})$.
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