Find the centroid of the triangle whose vertices are:$(1, 4), (-1, -1), (3, -2)$

Given:

The points $(1, 4), (-1, -1), (3, -2)$ are the vertices of a triangle.

To do:

We have to find the centroid of the given triangle.

Solution:

We know that,

Coordinates of the centroid of a triangle are $(\frac{Sum\ of\ abscissa}{3}, \frac{Sum\ of\ ordinates}{3})$

Therefore,

The coordinates of the centroid of the given triangle are,

$(\frac{1+(-1)+3}{3}, \frac{4+(-1)+(-2)}{3})$

$=(\frac{3}{3}, \frac{4-3}{3})$

$=(1, \frac{1}{3})$

The centroid of the given triangle is $(1, \frac{1}{3})$.