Find the 60th term of the A.P. 8, 10, 12, ……., if it has a total of 60 terms and hence find the sum of its last 10 terms.


Given: A.P. 8, 10, 12, ……., if it has a total of 60 terms 

To do: Find the 60th term of the A.P. and find the sum of its last 10 terms.

Solution:

The given A.P. 8, 10, 12, …

Here the first term $a= 8$ and the common difference $d=10 ‐ 8 = 2$ 

As known 

$n^{th}$ term of an A.P., $a_{n}=a+(n-1)d$

Its $60^{th}$ term $a_{60}=8+(60-1)2$

$=124$

As known sum of n terms in an A.P., $S_{n}=\frac{n}{2}( 2a+( n-1) d)$

We need to find the sum of the last 10 terms.

Thus,

Sum of last 10 terms $=$Sum of first 60 terms$ ‐$ Sum of first 50 terms

Thus the sum of last 10 terms $=S_{60} -S_{50}=\frac{60}{2}( 2\times 8+59\times 2) -\frac{50}{2}( 2\times 8+49\times 2)$

$=30( 134)-25( 114)$

$=4020-2850$

$=1170$

$\boxed{Therefore,\ Sum\ of\ last\ 10\ terms\ of\ the\ given\ A.P.\ is\ 1170.}$

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Updated on: 10-Oct-2022

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