Find the $5^{th}$ term from the end of the A.P. 10, 7, 4, ....., -65.
Given: An A.P. $10,\ 7,\ 4,\ .....,\ -65$.
To do: To find the $5^{th}$ term from the end of the A.P.
Solution:
Given A.P. is $10,\ 7,\ 4,\ .....,\ -65$.
Here, First term $a=10$
Common difference $d=-3$
Last term $l=-65$
$n=5$
Its $5^{th}$ term from the end $=l-( n-1)d$
$=-65-( 5-1)( -3)$
$=-65-( 4)( -3)$
$=-65+12$
$=-53$
Thus, the $5^{th}$ term from the end of A.P. is $-53$.
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