Find the 12th term from the end of the following arithmetic progressions:$3, 8, 13,…, 253$

Given:

Given A.P. is $3, 8, 13,…, 253$.
To do:

We have to find the 12th term from the end of the given arithmetic progression.
Solution:

In the given A.P.,

$a_1=3, a_2=8, a_3=13$

First term $a_1 = a= 3$, last term $l = 253$

Common difference $d = a_2-a_1 = 8 - 3 = 5$

We know that,

nth term from the end is given by $l - (n - 1 ) d$.

Therefore,

12th term from the end $= 253 - (12 - 1) \times 5 = 253 - 11 \times 5 = 253 - 55 = 198$.

The 12th term from the end of the given A.P. is $198$. 

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Updated on: 10-Oct-2022

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