Find the 12th term from the end of the following arithmetic progressions:$3, 5, 7, 9, … 201$

Given:

Given A.P. is $3, 5, 7, 9, … 201$.

To do:

We have to find the 12th term from the end of the given arithmetic progression.

Solution:

In the given A.P.,

$a_1=3, a_2=5, a_3=9$

First term $a_1 = a= 3$, last term $l = 201$

Common difference $d = a_2-a_1 = 5 - 3 = 2$

We know that,

nth term from the end is given by $l - (n - 1 ) d$.

Therefore,

12th term from the end $= 201 - (12 - 1) \times 2 = 201 - 11 \times 2 = 201 - 22 = 179$.

The 12th term from the end of the given A.P. is $179$.

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Updated on: 10-Oct-2022

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