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Find out HCF of $91,\ 112$ and $49$.
Given: Numbers $91,\ 112$ and $49$.
To do: To find the HCF of $91,\ 112$ and $49$.
Solution:
Given numbers are: $91,\ 112$ and $49$.
We do prime factorizations of $91,\ 112$ and $49$.
$91=7\times13$
$112=2\times2\times2\times2\times7$
$49=7\times7$
Here, we find $7$ as a common factor.
Thus, The HCF of $91,\ 112$ and $49$ is $7$.
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