Find HCF of the following
$x^2- 1, x^2 + 2^x - 3, x^2- 3x + 2$

Given: $x^2- 1, x^2 + 2^x - 3, x^2- 3x + 2$ 

To do: Find HCF

Solution:

$x^{2}-1, x^{2}+2x-3, x^{2}-3x+2$

=$x^{2}-1 = (x + 1)(x - 1)$

=$x^{2} + 2x - 3$

= $x^{2} + 3x - x - 3 = (x - 1) (x + 3)$

=$x^{2} - 3x + 2$ 

=$ x^{2} - 3x + 2  = x^{2} - 2x - x + 2$

=$ (x - 1) (x - 2)$ 

From the above, the HCF of given expressions is $(x-1)$

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

23 Views

Kickstart Your Career

Get certified by completing the course

Get Started