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# Find HCF of 24, 36, 108, 192.

Given:

Given numbers are 24, 36, 108 and 192.

To do:

We have to find the HCF of the given integers.

Solution:

Writing the numbers as a product of their prime factors:

Prime factorisation of 24:

- $2\ \times\ 2\ \times\ 2\ \times\ 3\ =\ 2^3\ \times\ 3^1$

Prime factorisation of 36:

- $2\ \times\ 2\ \times\ 2\ \times\ 3\ =\ 2^3\ \times\ 3^1$

Prime factorisation of 108:

- $2\ \times\ 2\ \times\ 3\ \times\ 3\ \times\ 3\ =\ 2^2\ \times\ 3^3$

Prime factorisation of 192:

- $2\ \times\ 2\ \times\ 2\ \times\ 2\ \times\ 2\ \times\ 2\ \times\ 3=\ 2^6\ \times\ 3^1$

Multiplying all common prime factors:

$2^2\ \times\ 3^1=4 \times 3$

$=12$

HCF(24, 36, 108, 192) $=$ **12**

**Therefore, HCF of 24, 36, 108, 192 is 12.**

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