Find Angle A in the below figure.
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Given:

$\angle BAC=3x^o$, $\angle ABC=5x^o$ and $\angle ACD=120^o$.
To do:

We have to find the measure of angle A.

Solution:

We know that,

The measure of each exterior angle of a triangle is equal to the sum of the opposite and non-adjacent interior angles.
Therefore,

$3x^o+5x^o=120^o$

$8x^o=120^o$

$x=\frac{120^o}{8}$

$x=15^o$

$3x^o=3(15^o)=45^o$

The measure of angle A is $45^o$.

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Updated on: 10-Oct-2022

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