Find ' $ a $ ' so that the statement becomes true
(i) $ 37+59=59+a $
(ii) $ 43+a=48+43 $
(iii) $ (43+a)+77=43+(95+77) $
(iv) $ (4+11)+17=(4+a)+11 $

Given:

(i) \( 37+59=59+a \)
(ii) \( 43+a=48+43 \)
(iii) \( (43+a)+77=43+(95+77) \)
(iv) \( (4+11)+17=(4+a)+11 \)

To do:

We have to find the values of $a$.

Solution:

(i) $37+59=59+a$

$\Rightarrow a=37+59-59$

$\Rightarrow a=37$
(ii) $43+a=48+43$

$\Rightarrow a=48+43-43$

$\Rightarrow a=48$

(iii) $(43+a)+77=43+(95+77)$

$\Rightarrow 43+a+77=43+95+77$

$\Rightarrow a=95+43-43+77-77$

$\Rightarrow a=95$

(iv) $(4+11)+17=(4+a)+11$

$\Rightarrow 4+11+17=4+a+11$

$\Rightarrow a=4-4+11-11+17$

$\Rightarrow a=17$ 

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Updated on: 10-Oct-2022

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