Find a quadratic polynomial, the sum and product of whose zeroes are $-8$ and $12$ respectively. Hence find the zeroes.
Given: A quadratic polynomial, the sum and product of whose zeroes are $-8$ and $12$ respectively.
To do: To find the zeroes.
Solution:
Let $\alpha$ and $\beta$ are the zeroes of the quadratic polynomial.
As given,
The sum of the zeroes$=\alpha+\beta=-8$
Product of the zeroes$=\alpha\beta=12$
The quadratic polynomial:
$x^2-( \alpha+\beta)x+\alpha\beta=0$
$\Rightarrow x^2-( -8)x+12=0$
$\Rightarrow x^2+8x+12=0$
Thus, the quadratic polynomial is $x^2+8x+12=0$.
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