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Find a pair of prime numbers whose difference is 2.
A) 71 and 73
B) 81 and 83
C) 95 and 97
D) 53 and 55p>
To do:
We have to find the pair of prime numbers whose difference is 2, from the given pairs.
Solution:
Prime Number: A number which has exactly two factors, which are one and the number itself.
A) 71 and 73
Factors of 71 = 1 , 71
Factors of 73 = 1 , 73
So, 71 and 73 are prime numbers.
Difference between the numbers is $73-71=2$.
B) 81 and 83
Factors of 81 = 1 , 3 , 9 , 27 , 81
81 has more than two factors. So, 81 is not a prime number.
C) 95 and 97
Factors of 95 = 1 , 5 , 19 , 95
95 has more than two factors. So, 95 is not a prime number.
D) 53 and 55
Factors 55 = 1 , 5 , 11 , 55
55 has more than two factors. So, 55 is not a prime number.
71 and 73 have exactly two factors. So, 71 and 73 are prime numbers.
73$-$71 = 2
The pair of prime numbers whose difference is 2 is 71 and 73.
Therefore, option (A) is correct.
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