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Find A, if $ 2020^{20}-2020^{19}=2020^{19} \times \mathrm{A} $.
Given:
\( 2020^{20}-2020^{19}=2020^{19} \times \mathrm{A} \).
To do:
We have to find the value of A.
Solution:
$2020^{20}-2020^{19}=2020\times2020^{19}-2020^{19}$
$=2020^{19}(2020-1)$ (Taking $2020^{19}$ common)
$=2020^{19}\times2019$
$2020^{19}\times A =2020^{19}\times2019$
Comparing both sides, we get,
$A=2019$.
The value of A is 2019.
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