Factorize: $x^{3}-23x^{2}+142x-120$.

Given: A polynomial: $x^{3}-23x^{2}+142 x-120$.


To do: To factorise the given polynomial.

Solution:

Given polynomial:


$x^{3}-23x^{2}+142x-120$


$=x^3-x^2-22x^2+22x+120x-120$

$=x^2( x-1)-22x( x-1)+120( x-1)$

$=( x-1)( x^2-22x+120)$

$=( x-1)( x^2-12x-10x+120)$

$=( x-1)( x( x-12)-10( x-12))$

$=( x-1)( x-10)( x-12)$

Updated on: 10-Oct-2022

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