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Factorize the expressions: $n^2-19n-92$.
Given: The expression:$n^2-19n-92$
To do: To factorize the expression:$n^2-19n-92$
Solution:
As given
$n^2-19n-92$
$=n^2-23n+4n-92$
$=n( n-23)+4( n-23)$
$=( n-23)( n+4)$
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