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Factorize the expression: $( l+m)^2-( l-m)^2$.
Given: The expression: $( l+m)^2-( l-m)^2$.
To do: To factorize the expression: $( l+m)^2-( l-m)^2$.
Solution:
As given, $(l+m)^2-(l-m)^2$
$=[( l+m)-( l-m)][( l+m)+( l-m)]$
$=( l+m-l+m)( l+m+l-m)$
$=( 2m) ( 2l)=4lm$
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