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Factorize the equation
$z^{2}-4z-12$
Given:$z^{2}-4z-12$
To Do: Factorize
Solution:
$z^{2}-4z-12$
$z^{2}-6z+2z-12$
$z(z-6)+2(z-6)$
$(z-6)(z-2)$
Therefore after factorizing $z^{2}-4z-12$ we get $(z-6)(z-2)$
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