Factorize:$2a^2 + 2\sqrt{6}ab +3b^2$

Given :

$2a^2 + 2\sqrt{6}ab +3b^2$

To do :

We have to factorize the given expression.

Solution :

$2a^2 + 2\sqrt{6}ab +3b^2 = (\sqrt{2}a)^2+ 2\times \sqrt{2}a \times \sqrt{3}b+ (\sqrt{3}b)^2$

$= (\sqrt{2}a + \sqrt{3}b)^2$

Hence, $2a^2 + 2\sqrt{6}ab +3b^2 = (\sqrt{2}a + \sqrt{3}b)^2$.

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Updated on: 10-Oct-2022

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