Factorize each of the following expressions:$64a^3 - b^3$


Given:

$64a^3 - b^3$

To do:

We have to factorize the given expression.

Solution:

We know that,

$a^3 + b^3 = (a + b) (a^2 - ab + b^2)$

$a^3 - b^3 = (a - b) (a^2 + ab + b^2)$

Therefore,

$64a^3 - b^3 = (4a)^3 - (b)^3$

$= (4a - b) [(4a)^2 + 4a \times b + (b)^2]$

$= (4a - b) (16a^2 + 4ab + b^2)$

Hence, $64a^3 - b^3 = (4a - b) (16a^2 + 4ab + b^2)$.

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Updated on: 10-Oct-2022

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