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Factorize : $3xy+2+3y+2x$
Given :
Given expression is $3xy+2+3y+2x$
To do :
We have to factorise $3xy+2+3y+2x$.
Solution :
$3xy+2+3y+2x = 3xy+3y+2x+2$
$= 3y(x+1)+2(x+1)$
$= (3y+2)(x+1)$
Therefore, the factors of $3xy+2+3y+2x$ are $(x+1)$ and $(3y+2)$.
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